# Chemical Equation | Chapter 1 | Chemical Reaction and Equation | Class 10

Question 1 What is a chemical equation?

Question 2 Give an example of chemical equation?

Question 3 What is a balanced equation?

Question 4 What is an unbalanced equation?

Question 5 What are the steps of balancing the equation?

**Chemical Equation**

The method of representing a chemical reaction with the help of symbols and formula is called chemical equation.

**For Ex:**

Zinc+Sulphuric acid————->Zinc Sulphate+Hydrogen

Reactants Products

The reactants are always written on left hand side in an equation with a plus sign between the.

The products are always written on right hand side in an equation with a plus sign between them.

A chemical equation is the short hand method of representing chemical reaction.

**Balanced Equation**:It has equal number of atoms of different elements in reactants and products.

Atom | Reactant | Product |

Zn | 1 | 1 |

H | 2 | 2 |

S | 1 | 1 |

O | 4 | 4 |

Unbalanced Equation:It has unequal number of atoms of different elements in reactants and products.

H_{2} + O_{2} —> H_{2}O

Atoms | Reactants | Products |

H | 2 | 2 |

O | 2 | 1 |

__Balancing of chemical equation__

The process of making the number of different types of atoms equal on both side of an equation is called balancing equation.

**Steps to balance chemical equation**

1)Write down the chemical reaction in the form of word equation,keeping reactants on left hand side and products on right hand side.

2)Write symbol and formula of all reactants and products in word equation.

3)Balance the equation by multiplying the symbols and formula by smallest possible figures.

4)Make the equation informative by indicating physical state,heat changes,reaction condition.

5)Indicate the physical state of reactant and products in an equation.we use the symbols as:solid(s),liquid(l),gas(g).

**Ex of balancing the equation**

**1)**CH_{4 +}O_{2 ————>}CO_{2 +}H_{2}O

Step 1:Make H atoms equal(Multiply products by 2)

CH_{4 +}O_{2 ————>}CO_{2 +2}_{ }H_{2}O

Step 2: Multiply oxygen of reactants by 2

CH_{4 +}_{ }** _{2}**O

_{2 ————>}CO

_{2 +}

_{2}_{ }H

_{2}O

_{Balanced equation}**2) **CH_{4 + }NaOH ————->** **Cu(OH)_{2+}Na_{2}SO_{4}

Step 1) Multiply sodium hydroxide by 2

CH_{4 +}_{2}_{ }NaOH ————->** **Cu(OH)_{2+}Na_{2}SO_{4 Balanced equation}

_{3)}_{ }** **Fe_{+ }H_{2}O————-> Fe_{3}O_{4 + }H_{2}

Step 1) Multiply Fe by 3 on left hand side

3 Fe_{+ }H_{2}O————-> Fe_{3}O_{4 + }H_{2}

Step 2)Multiply oxygen by 4 on left hand side

3 Fe_{+ 4 }H_{2}O————-> Fe_{3}O_{4 + }H_{2}

Step 3)Multiply hydrogen by 4 on right hand side

3 Fe_{+ 4 }H_{2}O————-> Fe_{3}O_{4 +}_{4 }H_{2 }_{ Balanced equation}

Nice many many thanks for it.

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