Exercise 14.1Exercise 14.2Exercise 14.3Exercise 14.4Exercise 14.5Exercise 14.6 |

**NCERT Answers for Class 6 Maths**

Chapter 14 Practical Geometry Exercise 14.3

Chapter 14 Practical Geometry Exercise 14.3

**Page 279**

**Ex 14.3 Class 6 Maths Question 1. Draw any line segment \(\overline {\bf PQ }\). Without measuring \(\overline {\bf PQ }\), construct a copy of \(\overline {\bf PQ }\).**

**Answer**

**Step 1:** Draw **\(\overline {\bf PQ }\)** of unknown length.

**Step 2:** Draw a line l and mark a point A on it.

**Step 3:** Open the compass equal to PQ.

**Step 4:** Place the needle of the compass at A and mark a point B on l.

Thus, **\(\overline {\bf AB }\) **is a copy of **\(\overline {\bf PQ }\)**.

**Ex 14.3 Class 6 Maths Question 2. Given some line segment \(\overline {\bf AB }\), whose length you do not know, construct PQ such that the length of \(\overline {\bf PQ }\) is twice that of \(\overline {\bf AB }\).**

**Answer**

**Step 1:** Draw **\(\overline {\bf AB }\)** of any suitable length.

**Step 2:** Place the needle of the compass at A and the other pencil end at B.

**Step 3:** Draw a line l and take a point P on it.

**Step 4:** With the same opening of the compass, place the needle at P and mark another point X on l.

**Step 5:** Now keeping compass open with same length, we keep pointed end on X and draw an arc on line l.

Thus **\(\overline {\bf PQ }\)** is the required line segment whose length is twice the length of **\(\overline {\bf AB }\)** i.e **\(\overline {\bf PQ }\)** = **\(\overline {\bf 2AB }\)**.

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