Exercise 14.2

Exercise 14.1 Exercise 14.2 Exercise 14.3 Exercise 14.4 Exercise 14.5 Exercise 14.6

NCERT Answers for Class 6 Maths
Chapter 14 Practical Geometry Exercise 14.2

Page 278

Ex 14.2 Class 6 Maths Question 1. Draw a line segment of length 7.3 cm using a ruler.

Answer

Ex 14.2 Class 6 Maths Question 2. Construct a line segment of length 5.6 cm using ruler and compasses.

Answer

Step 1: Draw any line L of suitable lengths.

Step 2: Place the needle of the compass on the zero mark of the ruler and open it up to 5.6 mark.

Step 3: Place the needle at any point A at the line and draw an arc to cut l at B.

Thus, \(\overline {\bf AB }\) is the required line segment of length 5.6 cm.

Ex 14.2 Class 6 Maths Question 3. Construct \(\overline {\bf AB }\) of length 7.8 cm. From this, cut off \(\overline {\bf AC}\) of length 4.7 cm. Measure \(\overline {\bf BC }\) .

Answer

Given that \(\overline {\bf AB }\) = 7.8 cm and \(\overline {\bf AC }\) = 4.7 cm.
Step 1: Place zero mark of the ruler at A.

Step 2: Mark a point B at a distance of 7.8 cm from A.

Step 3: Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.

Step 4: On measuring the length of BC, we find that \(\overline {\bf BC }\)= 3.1 cm.

Ex 14.2 Class 6 Maths Question 4. Given \(\overline {\bf AB }\) of length 3.9 cm. Construct \(\overline {\bf PQ }\) such that the length of \(\overline {\bf PQ }\) is twice that of \(\overline {\bf AB }\). Verify by measurement.

(Hint : Construct \(\overline {\bf PX }\) such that the length of \(\overline {\bf PX }\) = length of \(\overline {\bf AB }\) then cut off \(\overline {\bf XQ }\) such that \(\overline {\bf XQ }\) also has the length of \(\overline {\bf AB }\).

Answer

Step 1: Draw a line l and mark a point P on it. Let AB be the given line segment of 3.9 cm.

Step 2: By adjusting the compasses up to the length of AB, place the pointer of compasses at point P and draw an arc to cut the line at X.

Step 3: Again place the pointer on point X, draw an arc to cut line l at point Q.

\(\overline {\bf PQ }\) is the required line segment. Using the ruler we may measure the length of which comes to 7.8 cm.

Ex 14.2 Class 6 Maths Question 5. Given \(\overline {\bf AB }\) of length 7.3 cm and \(\overline {\bf CD }\) of length 3.4 cm, construct a line segment \(\overline {\bf XY }\) such that the length of \(\overline {\bf XY }\) is equal to the difference between the lengths of \(\overline {\bf AB }\) and \(\overline {\bf CD }\). Verify by measurement.

Answer

Steps of Construction

Step 1: Construct \(\overline {\bf AB }\) = 7.3 cm and \(\overline {\bf CD }\) = 3.4 cm.

Step 2: Measure \(\overline {\bf AB }\) = 7.3 cm using compass

Step 3: Now keeping compass opened the same length, we keep pointed end at x and draw the arc on line l.

So, \(\overline {\bf XB }\) = \(\overline {\bf AB }\) = 7.3 cm

Measure \(\overline {\bf CD }\) = 3.4 cm using compass

Step 4: Now keeping compass open the same length, we keep pointed end at point B and draw the arc on line l.

So, \(\overline {\bf YB }\) = \(\overline {\bf CD }\) = 3.4 cm

Thus, required the line segment \(\overline {\bf XY }\) = 3.9 cm