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You are here: Home / NCERT Solutions / Class 6 / Maths / Chapter 14 Practical Geometry / Exercise 14.2

Exercise 14.2

Last Updated on September 25, 2020 By Mrs Shilpi Nagpal Leave a Comment

Exercise 14.1
Exercise 14.2
Exercise 14.3
Exercise 14.4
Exercise 14.5
Exercise 14.6

NCERT Answers for Class 6 Maths
Chapter 14 Practical Geometry Exercise 14.2

Page 278

Ex 14.2 Class 6 Maths Question 1. Draw a line segment of length 7.3 cm using a ruler.

Answer

Steps of Construction:

 

Step 1: Mark a point A on the plane of the paper and place the ruler so that zero mark of the ruler is at A
Ex 14.2 Class 6 Maths Answer 1
Step 2: Mark with pencil a point B against the mark on the ruler which indicates 7.3 cm.

Step 3: Join points A and B by moving the tip of the pencil against the straight edge of the ruler.

The line segment AB so obtained is the required line segment.


Ex 14.2 Class 6 Maths Question 2. Construct a line segment of length 5.6 cm using ruler and compasses.

Answer

Step 1: Draw any line L of suitable lengths.

Step 2: Place the needle of the compass on the zero mark of the ruler and open it up to 5.6 mark.


Step 3: Place the needle at any point A at the line and draw an arc to cut l at B.Ex 14.2 Class 6 Maths Answer 2

Thus, \(\overline {\bf AB }\) is the required line segment of length 5.6 cm.

Ex 14.2 Class 6 Maths Question 3. Construct \(\overline {\bf AB }\) of length 7.8 cm. From this, cut off \(\overline {\bf AC}\) of length 4.7 cm. Measure \(\overline {\bf BC }\) .

Answer

Given that \(\overline {\bf AB }\) = 7.8 cm and \(\overline {\bf AC }\) = 4.7 cm.
Step 1: Place zero mark of the ruler at A.

Step 2: Mark a point B at a distance of 7.8 cm from A.


Step 3: Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.


Step 4: On measuring the length of BC, we find that \(\overline {\bf BC }\)= 3.1 cm.

Ex 14.2 Class 6 Maths Answer 3


Ex 14.2 Class 6 Maths Question 4. 
Given \(\overline {\bf AB }\) of length 3.9 cm. Construct \(\overline {\bf PQ }\) such that the length of \(\overline {\bf PQ }\) is twice that of \(\overline {\bf AB }\). Verify by measurement.

Ex 14.2 Class 6 Maths Question 4

(Hint : Construct \(\overline {\bf PX }\) such that the length of \(\overline {\bf PX }\) = length of \(\overline {\bf AB }\) then cut off \(\overline {\bf XQ }\) such that \(\overline {\bf XQ }\) also has the length of \(\overline {\bf AB }\).

Answer

Step 1: Draw a line l and mark a point P on it. Let AB be the given line segment of 3.9 cm.

Ex 14.2 Class 6 Maths Answer 4

Step 2: By adjusting the compasses up to the length of AB, place the pointer of compasses at point P and draw an arc to cut the line at X.

Step 3: Again place the pointer on point X, draw an arc to cut line l at point Q.

Ex 14.2 Class 6 Maths Answer 4

\(\overline {\bf PQ }\) is the required line segment. Using the ruler we may measure the length of which comes to 7.8 cm.

Ex 14.2 Class 6 Maths Question 5. Given \(\overline {\bf AB }\) of length 7.3 cm and \(\overline {\bf CD }\) of length 3.4 cm, construct a line segment \(\overline {\bf XY }\) such that the length of \(\overline {\bf XY }\) is equal to the difference between the lengths of \(\overline {\bf AB }\) and \(\overline {\bf CD }\). Verify by measurement.

Answer

Steps of Construction

Step 1: Construct \(\overline {\bf AB }\) = 7.3 cm and \(\overline {\bf CD }\) = 3.4 cm.

Ex 14.2 Class 6 Maths Answer 5

Step 2: Measure \(\overline {\bf AB }\) = 7.3 cm using compass

Step 3: Now keeping compass opened the same length, we keep pointed end at x and draw the arc on line l.

So, \(\overline {\bf XB }\) = \(\overline {\bf AB }\) = 7.3 cm

Measure \(\overline {\bf CD }\) = 3.4 cm using compassEx 14.2 Class 6 Maths Answer 5

Step 4: Now keeping compass open the same length, we keep pointed end at point B and draw the arc on line l.

So, \(\overline {\bf YB }\) = \(\overline {\bf CD }\) = 3.4 cm

Thus, required the line segment \(\overline {\bf XY }\) = 3.9 cm

Filed Under: Chapter 14 Practical Geometry, Class 6, Maths, NCERT Solutions

About Mrs Shilpi Nagpal

Author of this website, Mrs Shilpi Nagpal is MSc (Hons, Chemistry) and BSc (Hons, Chemistry) from Delhi University, B.Ed (I. P. University) and has many years of experience in teaching. She has started this educational website with the mindset of spreading Free Education to everyone.

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