Exercise 14.1Exercise 14.2Exercise 14.3Exercise 14.4Exercise 14.5Exercise 14.6 |

**NCERT**** Answers for Class 6 Maths**

Chapter 14 Practical Geometry Exercise 14.2

Chapter 14 Practical Geometry Exercise 14.2

**Page 278**

**Ex 14.2 Class 6 Maths Question 1. Draw a line segment of length 7.3 cm using a ruler.
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**Answer**

Steps of Construction:

**Step 1:**Mark a point A on the plane of the paper and place the ruler so that zero mark of the ruler is at A

**Step 2:**Mark with pencil a point B against the mark on the ruler which indicates 7.3 cm.

**Step 3:**Join points A and B by moving the tip of the pencil against the straight edge of the ruler.

The line segment AB so obtained is the required line segment.

Ex 14.2 Class 6 Maths Question 2. Construct a line segment of length 5.6 cm using ruler and compasses.

**Answer**

**Step 1:** Draw any line L of suitable lengths.

**Step 2:** Place the needle of the compass on the zero mark of the ruler and open it up to 5.6 mark.

**Step 3:** Place the needle at any point A at the line and draw an arc to cut l at B.

Thus, **\(\overline {\bf AB }\) ** is the required line segment of length 5.6 cm.

**Ex 14.2 Class 6 Maths Question 3. ****Construct \(\overline {\bf AB }\) of length 7.8 cm. From this, cut off \(\overline {\bf AC}\) of length 4.7 cm. Measure \(\overline {\bf BC }\) .**

**Answer**

Given that **\(\overline {\bf AB }\)** = 7.8 cm and **\(\overline {\bf AC }\)** = 4.7 cm.

**Step 1:** Place zero mark of the ruler at A.

**Step 2:** Mark a point B at a distance of 7.8 cm from A.

**Step 3:** Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.

**Step 4:** On measuring the length of BC, we find that **\(\overline {\bf BC }\)**= 3.1 cm.

Ex 14.2 Class 6 Maths Question 4. **Given \(\overline {\bf AB }\) of length 3.9 cm. Construct \(\overline {\bf PQ }\) such that the length of \(\overline {\bf PQ }\) is twice that of \(\overline {\bf AB }\). Verify by measurement.**

**(Hint : Construct \(\overline {\bf PX }\) such that the length of \(\overline {\bf PX }\) = length of \(\overline {\bf AB }\) then cut off \(\overline {\bf XQ }\) such that \(\overline {\bf XQ }\) also has the length of \(\overline {\bf AB }\).**

**Answer**

**Step 1:** Draw a line l and mark a point P on it. Let AB be the given line segment of 3.9 cm.

**Step 2:** By adjusting the compasses up to the length of AB, place the pointer of compasses at point P and draw an arc to cut the line at X.

**Step 3:** Again place the pointer on point X, draw an arc to cut line l at point Q.

**\(\overline {\bf PQ }\) **is the required line segment. Using the ruler we may measure the length of which comes to 7.8 cm.

**Ex 14.2 Class 6 Maths Question 5. Given \(\overline {\bf AB }\) of length 7.3 cm and \(\overline {\bf CD }\) of length 3.4 cm, construct a line segment \(\overline {\bf XY }\) such that the length of \(\overline {\bf XY }\) is equal to the difference between the lengths of \(\overline {\bf AB }\) and \(\overline {\bf CD }\). Verify by measurement.**

**Answer**

Steps of Construction

**Step 1:** Construct **\(\overline {\bf AB }\)** = 7.3 cm and **\(\overline {\bf CD }\)** = 3.4 cm.

**Step 2:** Measure **\(\overline {\bf AB }\) **= 7.3 cm using compass

**Step 3:** Now keeping compass opened the same length, we keep pointed end at x and draw the arc on line l.

So, **\(\overline {\bf XB }\)** = **\(\overline {\bf AB }\)** = 7.3 cm

Measure **\(\overline {\bf CD }\) **= 3.4 cm using compass

**Step 4:** Now keeping compass open the same length, we keep pointed end at point B and draw the arc on line l.

So, **\(\overline {\bf YB }\) = \(\overline {\bf CD }\) **= 3.4 cm

Thus, required the line segment **\(\overline {\bf XY }\) **= 3.9 cm

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