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You are here: Home / NCERT Solutions / Class 7 / Maths / NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Exercise 6.2

NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Exercise 6.2

Last Updated on February 24, 2022 By Mrs Shilpi Nagpal Leave a Comment

NCERT Solutions for Class 7 Maths
Chapter 6 The Triangle and its Properties
Exercise 6.2

  • Class 7 Maths Triangle and its Properties Exercise 6.1
  • Class 7 Maths Triangle and its Properties Exercise 6.2
  • Class 7 Maths Triangle and its Properties Exercise 6.3
  • Class 7 Maths Triangle and its Properties Exercise 6.4
  • Class 7 Maths Triangle and its Properties Exercise 6.5

1. Find the value of the unknown exterior angle x in the following diagrams:

Class 7 Maths Chapter 6 Triangle and its Properties Exercise 6.2

Answer

By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒  x=50°+ 70° = 120°
Hence, the exterior angle x is 120°.

(ii) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒  x= 65°+ 45°= 110°
Hence, the exterior angle x is 110°.

(iii) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒  x=30° + 40°= 70°
Hence, the exterior angle x is 70°.

(iv) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒ x= 60° + 60° = 120°
Hence, the exterior angle x is 120°.

(v) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
∴ x = 50° +50° = 100°
Hence, the exterior angle x is 100°.

(vi) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒ x = 30°+ 60° = 90°
Hence, the exterior angle x is 90°.

2. Find the value of the unknown interior angle x in the following figures:

Class 7 Maths Chapter 6 Triangle and its Properties Exercise 6.2 -2

Answer

We know that in a triangle, an exterior angle is equal to the sum of two interior opposite angles. Therefore
(i) Sum of interior opposite angles = Exterior angle
⇒ x+ 50°=115°
⇒ x = 115° – 50° = 65°
Hence, the value of the unknown interior angle x is 65°.

(ii) Sum of interior opposite angles = Exterior angle
⇒ x+ 70° =100°
⇒ x = 100° – 70° = 30°
Hence, the value of the unknown interior angle x is 30°.

(iii) Sum of interior opposite angles = Exterior angle
⇒ x+90° = 125°
⇒ x = 125° – 90°= 35°
Hence, the value of the unknown interior angle x is 35°.

(iv) Sum of interior opposite angles = Exterior angle
⇒ x+60° =120°
⇒ x=120° – 60° = 60°
Hence, the value of the unknown interior angle x is 60°.

(v) Sum of interior opposite angles = Exterior angle
⇒ x+ 30° = 80°
⇒ x= 80° – 30° = 50°
Hence, the value of the unknown interior angle x is 50°.

(vi) Sum of interior opposite angles = Exterior angle
⇒ x+35° = 75°
⇒ x = 75°- 35° = 40°
Hence, the value of the unknown interior angle x is 40°.

Filed Under: Class 7, Maths, NCERT Solutions

About Mrs Shilpi Nagpal

Author of this website, Mrs Shilpi Nagpal is MSc (Hons, Chemistry) and BSc (Hons, Chemistry) from Delhi University, B.Ed (I. P. University) and has many years of experience in teaching. She has started this educational website with the mindset of spreading Free Education to everyone.

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