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Home » NCERT Solutions » Class 7 » Maths » NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Exercise 6.2

NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Exercise 6.2

Last Updated on February 16, 2023 By Mrs Shilpi Nagpal

NCERT Solutions for Class 7 Maths
Chapter 6 The Triangle and its Properties
Exercise 6.2

  • Class 7 Maths Triangle and its Properties Exercise 6.1
  • Class 7 Maths Triangle and its Properties Exercise 6.2
  • Class 7 Maths Triangle and its Properties Exercise 6.3

1. Find the value of the unknown exterior angle x in the following diagrams:

Class 7 Maths Chapter 6 Triangle and its Properties Exercise 6.2

Answer

By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒  x=50°+ 70° = 120°
Hence, the exterior angle x is 120°.

(ii) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒  x= 65°+ 45°= 110°
Hence, the exterior angle x is 110°.

(iii) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒  x=30° + 40°= 70°
Hence, the exterior angle x is 70°.

(iv) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒ x= 60° + 60° = 120°
Hence, the exterior angle x is 120°.

(v) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
∴ x = 50° +50° = 100°
Hence, the exterior angle x is 100°.

(vi) By exterior angle property of a triangle,
Exterior angle = Sum of interior opposite angles
⇒ x = 30°+ 60° = 90°
Hence, the exterior angle x is 90°.

2. Find the value of the unknown interior angle x in the following figures:

Class 7 Maths Chapter 6 Triangle and its Properties Exercise 6.2 -2

Answer

We know that in a triangle, an exterior angle is equal to the sum of two interior opposite angles. Therefore
(i) Sum of interior opposite angles = Exterior angle
⇒ x+ 50°=115°
⇒ x = 115° – 50° = 65°
Hence, the value of the unknown interior angle x is 65°.(ii) Sum of interior opposite angles = Exterior angle
⇒ x+ 70° =100°
⇒ x = 100° – 70° = 30°
Hence, the value of the unknown interior angle x is 30°.

(iii) Sum of interior opposite angles = Exterior angle
⇒ x+90° = 125°
⇒ x = 125° – 90°= 35°
Hence, the value of the unknown interior angle x is 35°.

(iv) Sum of interior opposite angles = Exterior angle
⇒ x+60° =120°
⇒ x=120° – 60° = 60°
Hence, the value of the unknown interior angle x is 60°.

(v) Sum of interior opposite angles = Exterior angle
⇒ x+ 30° = 80°
⇒ x= 80° – 30° = 50°
Hence, the value of the unknown interior angle x is 50°.

(vi) Sum of interior opposite angles = Exterior angle
⇒ x+35° = 75°
⇒ x = 75°- 35° = 40°
Hence, the value of the unknown interior angle x is 40°.

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Filed Under: Class 7, Maths, NCERT Solutions

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