• Skip to main content
  • Skip to secondary menu
  • Skip to primary sidebar

Class Notes

Free Class Notes & Study Material

  • Class 1-5
  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • NCERT SOL
  • Ref Books
Home » Class 11 » Chemistry » Some Basic Concepts of Chemistry » Mole Concept in Solutions

Mole Concept in Solutions

Last Updated on July 3, 2023 By Mrs Shilpi Nagpal

A solution is defined as a homogeneous mixture of two or more chemically non reacting substances, the relative amount of which can be varied up to a certain limit.

If a solution consist of only two components it is called a binary solution.

The component present in smaller amount is called solute while the other present in larger amount is called solvent

The concentration of the solution can be expressed in number of ways:

(1) Mass percent or weight percent :Mass percent of a solute in a solution is the mass of the solute in grams present in 100 grams of solution.

mass percent

(2) Strength: Strength of a solution is defined as the amount of the solute in grams present per litre of the solution.

strength

(3) Molarity: Molarity of a solution is defined as the number of moles of the solute present per litre of the solution.It is represented by the symbol, M.

Molarity

(4)​ Molality :The molality of a solution is defined as number of moles of the solute dissolved in 1 kg of the solvent.

 

It is represented by the symbol m.

Molality

(5) Normality : Normality of a solution is defined as the number of gram equivalent of the solute present per litre of the solution.

It is represented by the symbol N.

Normality

Equivalent mass

Basicity is the number of displaceable H+ ions present in 1 molecule of the acid.

Acidity is the number of displaceable OH– ions present in 1 molecule of the base.

(6) Mole fraction : Mole fraction of any component in the solution is equal to the number of moles of that component divided by the total number of moles of all the components.

For a solution containing n2 moles of the solute dissolved in n1 moles of the solvent,

Mole fraction

Mole fraction

(7) Parts per million: The concentration of very dilute solution is expressed in terms of parts of the solute by mass present in million parts by mass of the solution.

Molarity equation

If a solution having molarity M1 and volume V1 is diluted to volume V2 so that the new molarity is M2 then as the total number of moles in the solution remains the same, we have :

Molarity equation

Normality Equation

Normality equation

Relation between molarity and normality of the solution of an acid or base

Normality of solution of an acid = Molarity × Basicity

Normality of solution of a base = Molarity × Acidity

Calculation of Molarity and Normality of the solution obtained on mixing two or more solution

If the solutions mixed are of the same substance 

If V1 mL of a solution of molarity M1 are mixed with V2 mL solution of the same substance with molarity M2 Or V1 mL of M1 HCL solution are mixed with V2 mL of M2 , then the molarity of the solution obtained is calculates as:

M1 V1 + M2 V2 = M3 (V1 +V2)

N1V1 + N2V2 = N3 (V1 +V2)

Filed Under: Chemistry, Class 11, Some Basic Concepts of Chemistry Tagged With: acidity, basicity, binary solution, mass percent, molality, molarity, molarity equation, mole fraction, normality, normality equation, parts per million, solute, solution, solvent, strength

About Mrs Shilpi Nagpal

Author of this website, Mrs. Shilpi Nagpal is MSc (Hons, Chemistry) and BSc (Hons, Chemistry) from Delhi University, B.Ed. (I. P. University) and has many years of experience in teaching. She has started this educational website with the mindset of spreading free education to everyone.

Reader Interactions

Comments

  1. Jkm says

    September 13, 2018 at 9:29 pm

    Bhot badiya sirg

  2. Gaurika Gupta says

    April 16, 2019 at 3:18 pm

    Very helpful.
    A hearty thanks to you.

  3. Mandeep says

    April 30, 2020 at 12:15 pm

    it’s really a very good deed . it is really helpful

  4. Cg says

    June 27, 2020 at 11:10 pm

    Thank You

  5. Ameer says

    September 7, 2020 at 7:25 pm

    Thank you mam

  6. Rishi says

    June 28, 2022 at 10:14 pm

    Thanks Mam for the explanation

Leave a Reply

Your email address will not be published. Required fields are marked *

Primary Sidebar

  • Facebook
  • Pinterest
  • Twitter
  • YouTube

CATEGORIES

  • —— Class 6 Notes ——
  • —— Class 7 Notes ——
  • —— Class 8 Notes ——
  • —— Class 9 Notes ——
  • —— Class 10 Notes ——
  • —— NCERT Solutions ——

© 2016 - 2025 · Disclaimer · Privacy Policy · About Us · Contact Us