• Skip to main content
  • Skip to secondary menu
  • Skip to primary sidebar

Class Notes

Free Class Notes & Study Material

  • Class 1-5
  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • NCERT SOL
  • Ref Books
Home » Class 11 » Chemistry » Ionic Equilibrium » Dissociation or Ionization of Acids And Bases

Dissociation or Ionization of Acids And Bases

Acids like HCl, H2SO4 ,HNO3 when dissolved in water dissociates almost completely thus producing a large number of H+ ions. These acids are called strong acids.

Acids like CH3COOH , HF, H2CO3, H3PO4 dissociates only to a small extent in the aqueous solution giving small amount of H+ ions and hence are called weak acids.

Bases like NaOH , KOH dissociate almost completely in the aqueous solution producing a large number of OH‾ ions and are called strong bases.

Bases like NH4OH , Ca(OH)2 , Al(OH)3  dissociate only to a small extent in the aqueous solution and are therefore called weak bases. 

The dissociation of weak acids or weak bases in water can be represented:

CH3COOH + H2O sign of equilibrium reaction CH3COO‾ + H3O+

NH3 + H2O sign of equilibrium reaction NH4+ (aq) + OH‾(aq)

If a weak acid is represented by HA , its dissociation in water can be represented by the equilbrium:

HA + H2O sign of equilibrium reaction  A‾ (aq) + H3O+ (aq)

Applying the law of chemical equilibrium, the expression constant will be:

Equilibrium constant for dissociation of weak acid

As water is solvent, its concentration is large and remains almost constant.

HA + (aq) sign of equilibrium reaction H+ (aq) + A‾ (aq)

equilibrium constant

 

Knowing the value of the dissociation constant of the acid, Ka and the concentration of the weak acid HA taken, concentration of H3O+ or H+ in the solution can be calculated as:

HA +aq sign of equilibrium reaction  H+ (aq) + A‾ (aq)

Initial conc of HA is C mol L‾1

Initial conc of H+ is 0 M

Initial conc of A‾ is 0 M

Final conc of HA at equilibrium is (C-x) M

Final conc of H+ at equilibrium is x M

Final conc of A‾ at equilibrium is x M

equilibrium constant

Ka = x × x / C-x

Ka = x2 / C- x

x is very small as compared to the initial concentration C ,x can be neglected in comparison to C.Hence the equation is simplified to the form:

Ka = x2 / C

x= √Ka × C

The dissociation of a weak base in water can be represented by the equilibrium:

BOH + aq sign of equilibrium reaction B+ (aq) + OH‾ (aq)

Dissociation of weak base

Filed Under: Chemistry, Class 11, Ionic Equilibrium Tagged With: dissociation of acid, dissociation of base, strong acid, strong base, weak acid, weak bases

Reader Interactions

Leave a Reply

Your email address will not be published. Required fields are marked *

Primary Sidebar

  • Facebook
  • Pinterest
  • Twitter
  • YouTube

CATEGORIES

  • —— Class 6 Notes ——
  • —— Class 7 Notes ——
  • —— Class 8 Notes ——
  • —— Class 9 Notes ——
  • —— Class 10 Notes ——
  • —— NCERT Solutions ——

© 2016 - 2025 · Disclaimer · Privacy Policy · About Us · Contact Us