• Skip to main content
  • Skip to secondary menu
  • Skip to primary sidebar

Class Notes

  • Home
  • Class 1-5
  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • NCERT Solutions
Home » NCERT Solutions » Class 7 » Maths » NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.3

NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.3

Last Updated on February 16, 2023 By Mrs Shilpi Nagpal

NCERT Solutions for Class 7 Maths
Chapter 4 Simple Equations
Exercise 4.3

  • Class 7 Maths Simple Equations Exercise 4.1
  • Class 7 Maths Simple Equations Exercise 4.2
  • Class 7 Maths Simple Equations Exercise 4.3
  • Class 7 Maths Simple Equations Exercise 4.4

1. Solve the following equations:
(a) 2y + (5/2) = (37/2)
(b) 5t + 28 = 10
(c) (a/5) + 3 = 2
(d) (q/4) + 7 = 5
(e) (5/2) x = -5
(f) (5/2) x = 25/4
(g) 7m + (19/2) = 13
(h) 6z + 10 = – 2
(i) (3/2) l = 2/3
(j) (2b/3) – 5 = 3

☛ Here, to solve given equations, separate the variable on LHS by applying suitable operation and apply same operation on RHS, also to get required solution

(a) 2y + (5/2) = (37/2)

Answer
By transposing (5/2) from LHS to RHS it becomes -5/2
Then,
= 2y = (37/2) – (5/2)
= 2y = (37-5)/2
= 2y = 32/2
Now, divide both side by 2,
= 2y/2 = (32/2)/2
= y = (32/2) × (1/2)
= y = 32/4
= y = 8

(b) 5t + 28 = 10

Answer
By transposing 28 from LHS to RHS it becomes -28
Then,
= 5t = 10 – 28
= 5t = – 18
Now, divide both side by 5,
= 5t/5= -18/5
= t = -18/5

(c) (a/5) + 3 = 2

Answer
By transposing 3 from LHS to RHS it becomes -3
Then,
= a/5 = 2 – 3
= a/5 = – 1
Now, multiply both side by 5,
= (a/5) × 5= -1 × 5
= a = -5

(d) (q/4) + 7 = 5

Answer
By transposing 7 from LHS to RHS it becomes -7
Then,
= q/4 = 5 – 7
= q/4 = – 2
Now,
Multiply both side by 4,
= (q/4) × 4= -2 × 4
= a = -8

(e) (5/2) x = -5

Answer
First we have to multiply both the side by 2,
= (5x/2) × 2 = – 5 × 2
= 5x = – 10
Now, we have to divide both the side by 5,
Then we get,
= 5x/5 = -10/5
= x = -2

(f) (5/2) x = 25/4

Answer
First we have to multiply both the side by 2,
= (5x/2) × 2 = (25/4) × 2
= 5x = (25/2)
Now, we have to divide both the side by 5,
Then we get,
= 5x/5 = (25/2)/5
= x = (25/2) × (1/5)
= x = (5/2)

(g) 7m + (19/2) = 13

Answer
By transposing (19/2) from LHS to RHS it becomes -19/2
Then,
= 7m = 13 – (19/2)
= 7m = (26 – 19)/2
= 7m = 7/2
Now, divide both side by 7,
= 7m/7 = (7/2)/7
= m = (7/2) × (1/7)
= m = ½

(h) 6z + 10 = – 2

Answer
By transposing 10 from LHS to RHS it becomes – 10
Then,
= 6z = -2 – 10
= 6z = – 12
Now, divide both side by 6,
= 6z/6 = -12/6
= m = – 2

(i) (3/2) l = 2/3

Answer
First we have to multiply both the side by 2,
= (3l/2) × 2 = (2/3) × 2
= 3l = (4/3)
Now, we have to divide both the side by 3,
Then we get,
= 3l/3 = (4/3)/3
= l = (4/3) × (1/3)
= x = (4/9)

(j) (2b/3) – 5 = 3

Answer
By transposing -5 from LHS to RHS it becomes 5|
Then,
= 2b/3 = 3 + 5
= 2b/3 = 8
Now, multiply both side by 3,
= (2b/3) × 3= 8 × 3
= 2b = 24
And, divide both side by 2,
= 2b/2 = 24/2
= b = 12

2. Solve the following equations:

(a) 2(x + 4) = 12                    (b) 3(n – 5) = 21                        (c) 3(n – 5) = – 21
(d) – 4(2 + x) = 8                   (e) 4(2 – x) = 8

Answer

(a) 2(x + 4) = 12
Let us divide both the side by 2,

= (2(x + 4))/2 = 12/2
= x + 4 = 6
By transposing 4 from LHS to RHS it becomes -4
= x = 6 – 4
= x = 2

(b) 3(n – 5) = 21
Let us divide both the side by 3,

= (3(n – 5))/3 = 21/3
= n – 5 = 7
By transposing -5 from LHS to RHS it becomes 5
= n = 7 + 5
= n = 12

(c) 3(n – 5) = – 21
Let us divide both the side by 3,

= (3(n – 5))/3 = – 21/3
= n – 5 = -7
By transposing -5 from LHS to RHS it becomes 5
= n = – 7 + 5
= n = – 2

(d) – 4(2 + x) = 8
Let us divide both the side by -4,

= (-4(2 + x))/ (-4) = 8/ (-4)
= 2 + x = -2
By transposing 2 from LHS to RHS it becomes – 2
= x = -2 – 2
= x = – 4

(e) 4(2 – x) = 8
Let us divide both the side by 4,

= (4(2 – x))/ 4 = 8/ 4
= 2 – x = 2
By transposing 2 from LHS to RHS it becomes – 2
= – x = 2 – 2
= – x = 0
= x = 0

3. Solve the following equations:
(a) 4 = 5(p – 2)                    (b) – 4 = 5(p – 2)                        (c) 16 = 4 + 3(t + 2)
(d) 4 + 5(p – 1) =34            (e) 0 = 16 + 4(m – 6)

(a) 4 = 5(p – 2) 
Let us divide both the side by 5,
= 4/5 = (5(p – 2))/5
= 4/5 = p -2
By transposing – 2 from RHS to LHS it becomes 2
= (4/5) + 2 = p
= (4 + 10)/ 5 = p
= p = 14/5

(b) – 4 = 5(p – 2)
Let us divide both the side by 5,

= – 4/5 = (5(p – 2))/5
= – 4/5 = p -2
By transposing – 2 from RHS to LHS it becomes 2
= – (4/5) + 2 = p
= (- 4 + 10)/ 5 = p
= p = 6/5

(c) 16 = 4 + 3(t + 2)
By transposing 4 from RHS to LHS it becomes – 4

= 16 – 4 = 3(t + 2)
= 12 = 3(t + 2)
Let us divide both the side by 3,
= 12/3 = (3(t + 2))/ 3
= 4 = t + 2
By transposing 2 from RHS to LHS it becomes – 2
= 4 – 2 = t
= t = 2

(d) 4 + 5(p – 1) =34
By transposing 4 from LHS to RHS it becomes – 4

= 5(p – 1) = 34 – 4
= 5(p – 1) = 30
Let us divide both the side by 5,
= (5(p – 1))/ 5 = 30/5
= p – 1 = 6
By transposing – 1 from RHS to LHS it becomes 1
= p = 6 + 1
= p = 7

(e) 0 = 16 + 4(m – 6)
By transposing 16 from RHS to LHS it becomes – 16

= 0 – 16 = 4(m – 6)
= – 16 = 4(m – 6)
Let us divide both the side by 4,
= – 16/4 = (4(m – 6))/ 4
= – 4 = m – 6
By transposing – 6 from RHS to LHS it becomes 6
= – 4 + 6 = m
= m = 2

4. (a) Construct 3 equations starting with x = 2
(b) Construct 3 equations starting with x = – 2

Answer

(a) Construct 3 equations starting with x = 2
First equation is,

Multiply both side by 6
= 6x = 12 … [equation 1]
Second equation is,
Subtracting 4 from both side,
= 6x – 4 = 12 -4
= 6x – 4 = 8 … [equation 2]
Third equation is,
Divide both side by 6
= (6x/6) – (4/6) = (8/6)
= x – (4/6) = (8/6) … [equation 3]

(b) Construct 3 equations starting with x = – 2
First equation is,

Multiply both side by 5
= 5x = -10 … [equation 1]
Second equation is,
Subtracting 3 from both side,
= 5x – 3 = – 10 – 3
= 5x – 3 = – 13 … [equation 2]
Third equation is,
Dividing both sides by 2
= (5x/2) – (3/2) = (-13/2) … [equation 3]

Share with Friends

Filed Under: Class 7, Maths, NCERT Solutions

Primary Sidebar

Recent Posts

  • Comet – I, Class 8 English, Chapter 9 Notes
  • Essay on Holi for Kids and Students
  • Jalebis, Class 8 English, Chapter 8 Notes
  • The Open Window, Class 8 English, Chapter 7 Notes
  • The Fight, Class 8 English, Chapter 6 Notes
  • Facebook
  • Pinterest
  • Twitter
  • YouTube

© 2016 - 2023 · Disclaimer · Privacy Policy · About Us · Contact Us