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Home » NCERT Solutions » Class 7 » Maths » NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.3

NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations Exercise 4.3

Last Updated on July 3, 2023 By Mrs Shilpi Nagpal

NCERT Solutions for Class 7 Maths
Chapter 4 Simple Equations
Exercise 4.3

  • Class 7 Maths Simple Equations Exercise 4.1
  • Class 7 Maths Simple Equations Exercise 4.2
  • Class 7 Maths Simple Equations Exercise 4.3
  • Class 7 Maths Simple Equations Exercise 4.4

1. Solve the following equations:
(a) 2y + (5/2) = (37/2)
(b) 5t + 28 = 10
(c) (a/5) + 3 = 2
(d) (q/4) + 7 = 5
(e) (5/2) x = -5
(f) (5/2) x = 25/4
(g) 7m + (19/2) = 13
(h) 6z + 10 = – 2
(i) (3/2) l = 2/3
(j) (2b/3) – 5 = 3

☛ Here, to solve given equations, separate the variable on LHS by applying suitable operation and apply same operation on RHS, also to get required solution

(a) 2y + (5/2) = (37/2)

Answer
By transposing (5/2) from LHS to RHS it becomes -5/2
Then,
= 2y = (37/2) – (5/2)
= 2y = (37-5)/2
= 2y = 32/2
Now, divide both side by 2,
= 2y/2 = (32/2)/2
= y = (32/2) × (1/2)
= y = 32/4
= y = 8

(b) 5t + 28 = 10

Answer
By transposing 28 from LHS to RHS it becomes -28
Then,
= 5t = 10 – 28
= 5t = – 18
Now, divide both side by 5,
= 5t/5= -18/5
= t = -18/5

(c) (a/5) + 3 = 2

Answer
By transposing 3 from LHS to RHS it becomes -3
Then,
= a/5 = 2 – 3
= a/5 = – 1
Now, multiply both side by 5,
= (a/5) × 5= -1 × 5
= a = -5

(d) (q/4) + 7 = 5

Answer
By transposing 7 from LHS to RHS it becomes -7
Then,
= q/4 = 5 – 7
= q/4 = – 2
Now,
Multiply both side by 4,
= (q/4) × 4= -2 × 4
= a = -8

(e) (5/2) x = -5

Answer
First we have to multiply both the side by 2,
= (5x/2) × 2 = – 5 × 2
= 5x = – 10
Now, we have to divide both the side by 5,
Then we get,
= 5x/5 = -10/5
= x = -2

(f) (5/2) x = 25/4

Answer
First we have to multiply both the side by 2,
= (5x/2) × 2 = (25/4) × 2
= 5x = (25/2)
Now, we have to divide both the side by 5,
Then we get,
= 5x/5 = (25/2)/5
= x = (25/2) × (1/5)
= x = (5/2)

(g) 7m + (19/2) = 13

Answer
By transposing (19/2) from LHS to RHS it becomes -19/2
Then,
= 7m = 13 – (19/2)
= 7m = (26 – 19)/2
= 7m = 7/2
Now, divide both side by 7,
= 7m/7 = (7/2)/7
= m = (7/2) × (1/7)
= m = ½

(h) 6z + 10 = – 2

Answer
By transposing 10 from LHS to RHS it becomes – 10
Then,
= 6z = -2 – 10
= 6z = – 12
Now, divide both side by 6,
= 6z/6 = -12/6
= m = – 2

(i) (3/2) l = 2/3

Answer
First we have to multiply both the side by 2,
= (3l/2) × 2 = (2/3) × 2
= 3l = (4/3)
Now, we have to divide both the side by 3,
Then we get,
= 3l/3 = (4/3)/3
= l = (4/3) × (1/3)
= x = (4/9)

(j) (2b/3) – 5 = 3

Answer
By transposing -5 from LHS to RHS it becomes 5|
Then,
= 2b/3 = 3 + 5
= 2b/3 = 8
Now, multiply both side by 3,
= (2b/3) × 3= 8 × 3
= 2b = 24
And, divide both side by 2,
= 2b/2 = 24/2
= b = 12

2. Solve the following equations:

(a) 2(x + 4) = 12                    (b) 3(n – 5) = 21                        (c) 3(n – 5) = – 21
(d) – 4(2 + x) = 8                   (e) 4(2 – x) = 8

Answer

(a) 2(x + 4) = 12
Let us divide both the side by 2,

= (2(x + 4))/2 = 12/2
= x + 4 = 6
By transposing 4 from LHS to RHS it becomes -4
= x = 6 – 4
= x = 2

(b) 3(n – 5) = 21
Let us divide both the side by 3,

= (3(n – 5))/3 = 21/3
= n – 5 = 7
By transposing -5 from LHS to RHS it becomes 5
= n = 7 + 5
= n = 12

(c) 3(n – 5) = – 21
Let us divide both the side by 3,

= (3(n – 5))/3 = – 21/3
= n – 5 = -7
By transposing -5 from LHS to RHS it becomes 5
= n = – 7 + 5
= n = – 2

(d) – 4(2 + x) = 8
Let us divide both the side by -4,

= (-4(2 + x))/ (-4) = 8/ (-4)
= 2 + x = -2
By transposing 2 from LHS to RHS it becomes – 2
= x = -2 – 2
= x = – 4

(e) 4(2 – x) = 8
Let us divide both the side by 4,

= (4(2 – x))/ 4 = 8/ 4
= 2 – x = 2
By transposing 2 from LHS to RHS it becomes – 2
= – x = 2 – 2
= – x = 0
= x = 0

3. Solve the following equations:
(a) 4 = 5(p – 2)                    (b) – 4 = 5(p – 2)                        (c) 16 = 4 + 3(t + 2)
(d) 4 + 5(p – 1) =34            (e) 0 = 16 + 4(m – 6)

(a) 4 = 5(p – 2) 
Let us divide both the side by 5,
= 4/5 = (5(p – 2))/5
= 4/5 = p -2
By transposing – 2 from RHS to LHS it becomes 2
= (4/5) + 2 = p
= (4 + 10)/ 5 = p
= p = 14/5

(b) – 4 = 5(p – 2)
Let us divide both the side by 5,

= – 4/5 = (5(p – 2))/5
= – 4/5 = p -2
By transposing – 2 from RHS to LHS it becomes 2
= – (4/5) + 2 = p
= (- 4 + 10)/ 5 = p
= p = 6/5

(c) 16 = 4 + 3(t + 2)
By transposing 4 from RHS to LHS it becomes – 4

= 16 – 4 = 3(t + 2)
= 12 = 3(t + 2)
Let us divide both the side by 3,
= 12/3 = (3(t + 2))/ 3
= 4 = t + 2
By transposing 2 from RHS to LHS it becomes – 2
= 4 – 2 = t
= t = 2

(d) 4 + 5(p – 1) =34
By transposing 4 from LHS to RHS it becomes – 4

= 5(p – 1) = 34 – 4
= 5(p – 1) = 30
Let us divide both the side by 5,
= (5(p – 1))/ 5 = 30/5
= p – 1 = 6
By transposing – 1 from RHS to LHS it becomes 1
= p = 6 + 1
= p = 7

(e) 0 = 16 + 4(m – 6)
By transposing 16 from RHS to LHS it becomes – 16

= 0 – 16 = 4(m – 6)
= – 16 = 4(m – 6)
Let us divide both the side by 4,
= – 16/4 = (4(m – 6))/ 4
= – 4 = m – 6
By transposing – 6 from RHS to LHS it becomes 6
= – 4 + 6 = m
= m = 2

4. (a) Construct 3 equations starting with x = 2
(b) Construct 3 equations starting with x = – 2

Answer

(a) Construct 3 equations starting with x = 2
First equation is,

Multiply both side by 6
= 6x = 12 … [equation 1]
Second equation is,
Subtracting 4 from both side,
= 6x – 4 = 12 -4
= 6x – 4 = 8 … [equation 2]
Third equation is,
Divide both side by 6
= (6x/6) – (4/6) = (8/6)
= x – (4/6) = (8/6) … [equation 3]

(b) Construct 3 equations starting with x = – 2
First equation is,

Multiply both side by 5
= 5x = -10 … [equation 1]
Second equation is,
Subtracting 3 from both side,
= 5x – 3 = – 10 – 3
= 5x – 3 = – 13 … [equation 2]
Third equation is,
Dividing both sides by 2
= (5x/2) – (3/2) = (-13/2) … [equation 3]

Filed Under: Class 7, Maths, NCERT Solutions

About Mrs Shilpi Nagpal

Author of this website, Mrs. Shilpi Nagpal is MSc (Hons, Chemistry) and BSc (Hons, Chemistry) from Delhi University, B.Ed. (I. P. University) and has many years of experience in teaching. She has started this educational website with the mindset of spreading free education to everyone.

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