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You are here: Home / NCERT Solutions / Class 7 / Maths / Chapter 2 Fractions and Decimals / Class 7 Maths Exercise 2.4

Class 7 Maths Exercise 2.4

Last Updated on August 26, 2020 By Mrs Shilpi Nagpal 1 Comment

NCERT Answers for Class 7 Maths
Chapter 2 Fractions and Decimals Exercise 2.4

Chapter 2  Exercise 2.1
Chapter 2  Exercise 2.2
Chapter 2  Exercise 2.3
Chapter 2 Exercise 2.5
Chapter 2 Exercise 2.6
Chapter 2 Exercise 2.7

Page 46

Ex 2.4 Class 7 Maths Question 1. Find

Ex 2.4 Class 7 Maths Question 1

(i) 12 ÷ 3/4

Answer

= 12 × reciprocal of 3/4

= 12 × (4/3)

= 4 × 4

= 16

(ii) 14 ÷ (5/6)

Answer

= 14 × reciprocal of (5/6)

= 14 × (6/5)

= 84/5

(iii) 8 ÷ (7/3)

Answer

= 8 × reciprocal of (7/3)

= 8 × (3/7)

= (24/7)

(iv) 4 ÷ (8/3)

Answer

= 4 × reciprocal of (8/3)

= 4 × (3/8)

= 1 × (3/2)

= 3/2

(v) 3 ÷ 2 x 1 by 3

Answer

= 2 x 1 by 3 = 7/3

= 3 ÷ (7/3)

= 3 × reciprocal of (7/3)

= 3 × (3/7)

= 9/7

(vi) 5 ÷ 3 x 4 by 7

Answer

=3 x 4 by 7= 25/7

 

= 5 ÷ (25/7)

= 5 × reciprocal of (25/7)

= 5 × (7/25)

= 1 × (7/5)

= 7/5

Ex 2.4 Class 7 Maths Question 2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.

Ex 2.4 Class 7 Maths Question 2

Answer

(i) Reciprocal of (3/7) is (7/3) [∵ ((3/7) × (7/3)) = 1]

So, it is an improper fraction.

Improper fraction is that fraction in which numerator is greater than its denominator.

(ii) 5/8

Answer

Reciprocal of (5/8) is (8/5) [∵ ((5/8) × (8/5)) = 1]

So, it is an improper fraction.

Improper fraction is that fraction in which numerator is greater than its denominator.

(iii) 9/7

Answer

Reciprocal of (9/7) is (7/9) [∵ ((9/7) × (7/9)) = 1]

So, it is a proper fraction.

A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.

(iv) 6/5

Answer

Reciprocal of (6/5) is (5/6) [∵ ((6/5) × (5/6)) = 1]

So, it is a proper fraction.

A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.

(v) 12/7

Answer

Reciprocal of (12/7) is (7/12) [∵ ((12/7) × (7/12)) = 1]

So, it is a proper fraction.

A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.

(vi) 1/8

Answer

Reciprocal of (1/8) is (8/1) or 8 [∵ ((1/8) × (8/1)) = 1]

So, it is a whole number.

Whole numbers are collection of all positive integers including 0.

(vii) 1/11

Answer

Reciprocal of (1/11) is (11/1) or 11 [∵ ((1/11) × (11/1)) = 1]

So, it is a whole number.

Whole numbers are collection of all positive integers including 0.

Ex 2.4 Class 7 Maths Question 3. Find :

Ex 2.4 Class 7 Maths Question 3

(i) (7/3) ÷ 2

Answer

= (7/3) × reciprocal of 2

= (7/3) × (1/2)

= (7 × 1) / (3 × 2)

= 7/6

= 1 x 1 by 6

(ii) (4/9) ÷ 5

Answer

= (4/9) × reciprocal of 5

= (4/9) × (1/5)

= (4 × 1) / (9 × 5)

= 4/45

(iii) (6/13) ÷ 7

Answer

= (6/13) × reciprocal of 7

= (6/13) × (1/7)

= (6 × 1) / (13 × 7)

= 6/91

(iv) 4 x 1 by 3 ÷ 3

Answer

=4 x 1 by 3= 13/3

 

= (13/3) × reciprocal of 3

= (13/3) × (1/3)

= (13 × 1) / (3 × 3)

= 13/9

(iv)3 x 1 by 2  ÷ 4

Answer

= 3 x 1 by 2 = 7/2

 

= (7/2) × reciprocal of 4

= (7/2) × (1/4)

= (7 × 1) / (2 × 4)

= 7/8

(iv)4 x 3 by 7  ÷ 7

Answer

=4 x 3 by 7= 31/7

 

= (31/7) × reciprocal of 7

= (31/7) × (1/7)

= (31 × 1) / (7 × 7)

= 31/49

Ex 2.4 Class 7 Maths Question 4. Find :

Ex 2.4 Class 7 Maths Question 4

(i) (2/5) ÷ (1/2)

Answer

= (2/5) × reciprocal of ½

= (2/5) × (2/1)

= (2 × 2) / (5 × 1)

= 4/5

(ii) (4/9) ÷ (2/3)

Answer

= (4/9) × reciprocal of (2/3)

= (4/9) × (3/2)

= (4 × 3) / (9 × 2)

= (2 × 1) / (3 × 1)

= 2/3

(iii) (3/7) ÷ (8/7)

Answer

= (3/7) × reciprocal of (8/7)

= (3/7) × (7/8)

= (3 × 7) / (7 × 8)

= (3 × 1) / (1 × 8)

= 3/8

(iv) 2 x 1 by 3 ÷ (3/5)

Answer

= 2 x 1 by 3= 7/3

 

= (7/3) × reciprocal of (3/5)

= (7/3) × (5/3)

= (7 × 5) / (3 × 3)

= 35/9

(v) 3 x 1 by 2 ÷ (8/3)

Answer

= 3 ½ = 7/2

 

= (7/2) × reciprocal of (8/3)

= (7/2) × (3/8)

= (7 × 3) / (2 × 8)

= 21/16

(vi) (2/5) ÷ 1 x 1 by 2

Answer

= 1 x 1 by 2 = 3/2

 

= (2/5) × reciprocal of (3/2)

= (2/5) × (2/3)

= (2 × 2) / (5 × 3)

= 4/15

(vii) 3 x 1 by 5 ÷ 1 x 2 by 3

Answer

=3 x 1 by 5= 16/5

=1 x 2 by 3= 5/3

 

= (16/5) × reciprocal of (5/3)

= (16/5) × (3/5)

= (16 × 3) / (5 × 5)

= 48/25

(viii)  2 x 1 by 5÷ 1 x 1 by 5

Answer

=2 x 1 by 5= 11/5

=1 x 1 by 5= 6/5

 

= (11/5) × reciprocal of (6/5)

= (11/5) × (5/6)

= (11 × 5) / (5 × 6)

= (11 × 1) / (1 × 6)

= 11/6

Filed Under: Chapter 2 Fractions and Decimals, Class 7, Maths, NCERT Solutions

About Mrs Shilpi Nagpal

Author of this website, Mrs Shilpi Nagpal is MSc (Hons, Chemistry) and BSc (Hons, Chemistry) from Delhi University, B.Ed (I. P. University) and has many years of experience in teaching. She has started this educational website with the mindset of spreading Free Education to everyone.

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  1. Aanshi jain says

    November 25, 2020 at 11:17 am

    Thank you for brilliant answers

    Reply

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