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Home » NCERT Solutions » Class 7 » Maths » Chapter 2 Fractions and Decimals » Class 7 Maths Exercise 2.4

Class 7 Maths Exercise 2.4

Last Updated on April 5, 2023 By Mrs Shilpi Nagpal

NCERT Answers for Class 7 Maths
Chapter 2 Fractions and Decimals Exercise 2.4

Chapter 2  Exercise 2.1
Chapter 2  Exercise 2.2
Chapter 2  Exercise 2.3
Chapter 2 Exercise 2.5
Chapter 2 Exercise 2.6
Chapter 2 Exercise 2.7

Page 46

Ex 2.4 Class 7 Maths Question 1. Find

Ex 2.4 Class 7 Maths Question 1

(i) 12 ÷ 3/4

Answer

= 12 × reciprocal of 3/4

= 12 × (4/3)

= 4 × 4

= 16

(ii) 14 ÷ (5/6)

Answer

= 14 × reciprocal of (5/6)

= 14 × (6/5)

= 84/5

(iii) 8 ÷ (7/3)

Answer

= 8 × reciprocal of (7/3)

= 8 × (3/7)

= (24/7)

(iv) 4 ÷ (8/3)

Answer

= 4 × reciprocal of (8/3)

= 4 × (3/8)

= 1 × (3/2)

= 3/2

(v) 3 ÷ 2 x 1 by 3

Answer

= 2 x 1 by 3 = 7/3

= 3 ÷ (7/3)

= 3 × reciprocal of (7/3)

= 3 × (3/7)

= 9/7

(vi) 5 ÷ 3 x 4 by 7

Answer

=3 x 4 by 7= 25/7

 

= 5 ÷ (25/7)

= 5 × reciprocal of (25/7)

= 5 × (7/25)

= 1 × (7/5)

= 7/5

Ex 2.4 Class 7 Maths Question 2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fractions, improper fractions and whole numbers.

Ex 2.4 Class 7 Maths Question 2

Answer

(i) Reciprocal of (3/7) is (7/3) [∵ ((3/7) × (7/3)) = 1]

So, it is an improper fraction.

Improper fraction is that fraction in which numerator is greater than its denominator.

(ii) 5/8

Answer

Reciprocal of (5/8) is (8/5) [∵ ((5/8) × (8/5)) = 1]

So, it is an improper fraction.

Improper fraction is that fraction in which numerator is greater than its denominator.

(iii) 9/7

Answer

Reciprocal of (9/7) is (7/9) [∵ ((9/7) × (7/9)) = 1]

So, it is a proper fraction.

A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.

(iv) 6/5

Answer

Reciprocal of (6/5) is (5/6) [∵ ((6/5) × (5/6)) = 1]

So, it is a proper fraction.

A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.

(v) 12/7

Answer

Reciprocal of (12/7) is (7/12) [∵ ((12/7) × (7/12)) = 1]

So, it is a proper fraction.

A proper fraction is that fraction in which denominator is greater than the numerator of the fraction.

(vi) 1/8

Answer

Reciprocal of (1/8) is (8/1) or 8 [∵ ((1/8) × (8/1)) = 1]

So, it is a whole number.

Whole numbers are collection of all positive integers including 0.

(vii) 1/11

Answer

Reciprocal of (1/11) is (11/1) or 11 [∵ ((1/11) × (11/1)) = 1]

So, it is a whole number.

Whole numbers are collection of all positive integers including 0.

Ex 2.4 Class 7 Maths Question 3. Find :

Ex 2.4 Class 7 Maths Question 3

(i) (7/3) ÷ 2

Answer

= (7/3) × reciprocal of 2

= (7/3) × (1/2)

= (7 × 1) / (3 × 2)

= 7/6

= 1 x 1 by 6

(ii) (4/9) ÷ 5

Answer

= (4/9) × reciprocal of 5

= (4/9) × (1/5)

= (4 × 1) / (9 × 5)

= 4/45

(iii) (6/13) ÷ 7

Answer

= (6/13) × reciprocal of 7

= (6/13) × (1/7)

= (6 × 1) / (13 × 7)

= 6/91

(iv) 4 x 1 by 3 ÷ 3

Answer

=4 x 1 by 3= 13/3

= (13/3) × reciprocal of 3

= (13/3) × (1/3)

= (13 × 1) / (3 × 3)

= 13/9

(iv)3 x 1 by 2  ÷ 4

Answer

= 3 x 1 by 2 = 7/2

= (7/2) × reciprocal of 4

= (7/2) × (1/4)

= (7 × 1) / (2 × 4)

= 7/8

(iv)4 x 3 by 7  ÷ 7

Answer

=4 x 3 by 7= 31/7

= (31/7) × reciprocal of 7

= (31/7) × (1/7)

= (31 × 1) / (7 × 7)

= 31/49

Ex 2.4 Class 7 Maths Question 4. Find :

Ex 2.4 Class 7 Maths Question 4

(i) (2/5) ÷ (1/2)

Answer

= (2/5) × reciprocal of ½

= (2/5) × (2/1)

= (2 × 2) / (5 × 1)

= 4/5

(ii) (4/9) ÷ (2/3)

Answer

= (4/9) × reciprocal of (2/3)

= (4/9) × (3/2)

= (4 × 3) / (9 × 2)

= (2 × 1) / (3 × 1)

= 2/3

(iii) (3/7) ÷ (8/7)

Answer

= (3/7) × reciprocal of (8/7)

= (3/7) × (7/8)

= (3 × 7) / (7 × 8)

= (3 × 1) / (1 × 8)

= 3/8

(iv) 2 x 1 by 3 ÷ (3/5)

Answer

= 2 x 1 by 3= 7/3

= (7/3) × reciprocal of (3/5)

= (7/3) × (5/3)

= (7 × 5) / (3 × 3)

= 35/9

(v) 3 x 1 by 2 ÷ (8/3)

Answer

= 3 ½ = 7/2

= (7/2) × reciprocal of (8/3)

= (7/2) × (3/8)

= (7 × 3) / (2 × 8)

= 21/16

(vi) (2/5) ÷ 1 x 1 by 2

Answer

= 1 x 1 by 2 = 3/2

= (2/5) × reciprocal of (3/2)

= (2/5) × (2/3)

= (2 × 2) / (5 × 3)

= 4/15

(vii) 3 x 1 by 5 ÷ 1 x 2 by 3

Answer

=3 x 1 by 5= 16/5

=1 x 2 by 3= 5/3

= (16/5) × reciprocal of (5/3)

= (16/5) × (3/5)

= (16 × 3) / (5 × 5)

= 48/25

(viii)  2 x 1 by 5÷ 1 x 1 by 5

Answer

=2 x 1 by 5= 11/5

=1 x 1 by 5= 6/5

= (11/5) × reciprocal of (6/5)

= (11/5) × (5/6)

= (11 × 5) / (5 × 6)

= (11 × 1) / (1 × 6)

= 11/6

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Filed Under: Chapter 2 Fractions and Decimals, Class 7, Maths, NCERT Solutions

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  1. Aanshi jain says

    November 25, 2020 at 11:17 am

    Thank you for brilliant answers

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