Integers form a bigger collection of numbers which contains whole numbers and negative numbers.
Integers Class 7 Exercise 1.1 |
NCERT Answers for Class 7 Maths Chapter 1 Integers Exercise 1.1
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Ex 1.1 Class 7 Maths Question 1. Following number line shows the temperature in degree celsius (°C) at different places on a particular day.
(a) Observe this number line and write the temperature of the places marked on it.
(b) What is the temperature difference between the hottest and the coldest places among the above?
(c) What is the temperature difference between Lahulspiti and Srinagar?
(d) Can we say temperature of Srinagar and Shimla taken together is less than the temperature at Shimla? Is it also less than the temperature at Srinagar?
Answer
(a) By observing the number line, we can find the temperature of the cities as follows,
Temperature at the Lahulspiti is -8^{o}C
Temperature at the Srinagar is -2^{o}C
Temperature at the Shimla is 5^{o}C
Temperature at the Ooty is 14^{o}C
Temperature at the Bengaluru is 22^{o}C
(b) From the number line we observe that,
The temperature at the hottest place i.e., Bengaluru is 22^{o}C
The temperature at the coldest place i.e., Lahulspiti is -8^{o}C
Temperature difference between hottest and coldest place is = 22^{o}C – (-8^{o}C)
= 22^{o}C + 8^{o}C
= 30^{o}C
Hence, the temperature difference between the hottest and the coldest place is 30^{o}C.
(c) From the given number line,
The temperature at the Lahulspiti is -8^{o}C
The temperature at the Srinagar is -2^{o}C
ThereforeThe temperature difference between Lahulspiti and Srinagar is = -2^{o}C – (8^{o}C)
= – 2^{O}C + 8^{o}C
= 6^{o}C
(d) From the given number line,
The temperature at Srinagar =-2^{o}C
The temperature at Shimla = 5^{o}C
The temperature of Srinagar and Shimla taken together is = – 2^{o}C + 5^{o}C
= 3^{o}C
Therefore 5^{o}C > 3^{o}C
So, the temperature of Srinagar and Shimla taken together is less than the temperature at Shimla.
Then, 3^{o} > -2^{o
}No, the temperature of Srinagar and Shimla taken together is not less than the temperature of Srinagar.
Ex 1.1 Class 7 Maths Question 2. In a quiz, positive marks are given for correct answers and negative marks are given for incorrect answers. If Jack’s scores in five successive rounds were 25, – 5, – 10, 15 and 10, what was his total at the end?
Answer
From the question,
Jack’s score in five successive rounds are 25, -5, -10, 15 and 10
The total score of Jack at the end will be = 25 + (-5) + (-10) + 15 + 10
= 25 – 5 – 10 + 15 + 10
= 50 – 15
= 35
Therefore, Jack’s total score at the end is 35.
Ex 1.1 Class 7 Maths Question3. At Srinagar temperature was – 5°C on Monday and then it dropped by 2°C on Tuesday. What was the temperature of Srinagar on Tuesday? On Wednesday, it rose by 4°C. What was the temperature on this day?
Answer
From the question,
Temperature on Monday at Srinagar = -5^{o}C
Temperature on Tuesday at Srinagar is dropped by 2^{o}C = Temperature on Monday – 2^{o}C
= -5^{o}C – 2^{o}C
= -7^{o}C
Temperature on Wednesday at Srinagar is rose by 4^{o}C = Temperature on Tuesday + 4^{o}C
= -7^{o}C + 4^{o}C
= -3^{o}C
Thus, the temperature on Tuesday and Wednesday was -7^{o}C and -3^{o}C respectively.
Ex 1.1 Class 7 Maths Question 4. A plane is flying at the height of 5000 m above the sea level. At a particular point, it is exactly above a submarine floating 1200 m below the sea level. What is the vertical distance between them?
Answer
From the question,
Plane is flying at the height = 5000 m
Depth of Submarine = -1200 m
The vertical distance between plane and submarine = 5000 m – (- 1200) m
= 5000 m + 1200 m
= 6200 m
Ex 1.1 Class 7 Maths Question 5. Mohan deposits ₹ 2,000 in his bank account and withdraws ₹ 1,642 from it, the next day. If withdrawal of amount from the account is represented by a negative integer, then how will you represent the amount deposited? Find the balance in Mohan’s account after the withdrawal.
Answer
Withdrawal of amount from the account is represented by a negative integer.
Then, deposit of amount to the account is represented by a positive integer.
From the question,
Total amount deposited in bank account by the Mohan = ₹ 2000
Total amount withdrawn from the bank account by the Mohan = – ₹ 1642
Balance in Mohan’s account after the withdrawal = amount deposited + amount withdrawn
= ₹ 2000 + (-₹ 1642)
= ₹ 2000 – ₹ 1642
= ₹ 358
Hence, the balance in Mohan’s account after the withdrawal is ₹ 358
Ex 1.1 Class 7 Maths Question 6. Rita goes 20 km towards east from a point A to the point B. From B, she moves 30 km towards west along the same road. If the distance towards east is represented by a positive integer then, how will you represent the distance travelled towards west? By which integer will you represent her final position from A ?
Ex 1.1 Class 7 Maths Question 7. In a magic square each row, column and diagonal have the same sum. Check whichof the following is a magic square.
5 | -1 | -4 |
-5 | -2 | 7 |
0 | 3 | -3 |
1 | -10 | 0 |
-4 | -3 | -2 |
-6 | 4 | -7 |
Answer
First we consider the square (i)
By adding the numbers in each rows we get,
= 5 + (- 1) + (- 4) = 5 – 1 – 4 = 5 – 5 = 0
= -5 + (-2) + 7 = – 5 – 2 + 7 = -7 + 7 = 0
= 0 + 3 + (-3) = 3 – 3 = 0
By adding the numbers in each columns we get,
= 5 + (- 5) + 0 = 5 – 5 = 0
= (-1) + (-2) + 3 = -1 – 2 + 3 = -3 + 3 = 0
= -4 + 7 + (-3) = -4 + 7 – 3 = -7 + 7 = 0
By adding the numbers in diagonals we get,
= 5 + (-2) + (-3) = 5 – 2 – 3 = 5 – 5 = 0
= -4 + (-2) + 0 = – 4 – 2 = -6
Because sum of one diagonal is not equal to zero,
So, (i) is not a magic square
Now, we consider the square (ii)
By adding the numbers in each rows we get,
= 1 + (-10) + 0 = 1 – 10 + 0 = -9
= (-4) + (-3) + (-2) = -4 – 3 – 2 = -9
= (-6) + 4 + (-7) = -6 + 4 – 7 = -13 + 4 = -9
By adding the numbers in each columns we get,
= 1 + (-4) + (-6) = 1 – 4 – 6 = 1 – 10 = -9
= (-10) + (-3) + 4 = -10 – 3 + 4 = -13 + 4
= 0 + (-2) + (-7) = 0 – 2 – 7 = -9
By adding the numbers in diagonals we get,
= 1 + (-3) + (-7) = 1 – 3 – 7 = 1 – 10 = -9
= 0 + (-3) + (-6) = 0 – 3 – 6 = -9
This (ii) square is a magic square, because sum of each row, each column and diagonal is equal to -9.
Ex 1.1 Class 7 Maths Question 8. Verify a – (– b) = a + b for the following values of a and b.
(i) a = 21, b = 18
(ii) a = 118, b = 125
(iii) a = 75, b = 84
(iv) a = 28, b = 11
Answer
(i) a = 21, b = 18
From the question,
a = 21 and b = 18
To verify a – (- b) = a + b
Let us take Left Hand Side (LHS) = a – (- b)
= 21 – (- 18)
= 21 + 18
= 39
Now, Right Hand Side (RHS) = a + b
= 21 + 18
= 39
By comparing LHS and RHS
LHS = RHS
39 = 39
Hence, the value of a and b is verified.
(ii) a = 118, b = 125
From the question,
a = 118 and b = 125
To verify a – (- b) = a + b
Let us take Left Hand Side (LHS) = a – (- b)
= 118 – (- 125)
= 118 + 125
= 243
Now, Right Hand Side (RHS) = a + b
= 118 + 125
= 243
By comparing LHS and RHS
LHS = RHS
243 = 243
Hence, the value of a and b is verified.
(iii) a = 75, b = 84
From the question,
a = 75 and b = 84
To verify a – (- b) = a + b
Let us take Left Hand Side (LHS) = a – (- b)
= 75 – (- 84)
= 75 + 84
= 159
Now, Right Hand Side (RHS) = a + b
= 75 + 84
= 159
By comparing LHS and RHS
LHS = RHS
159 = 159
Hence, the value of a and b is verified.
(iv) a = 28, b = 11
From the question,
a = 28 and b = 11
To verify a – (- b) = a + b
Let us take Left Hand Side (LHS) = a – (- b)
= 28 – (- 11)
= 28 + 11
= 39
Now, Right Hand Side (RHS) = a + b
= 28 + 11
= 39
By comparing LHS and RHS
LHS = RHS
39 = 39
Hence, the value of a and b is verified.
Ex 1.1 Class 7 Maths Question 9. Use the sign of >, < or = in the box to make the statements true.
(a) (– 8) + (– 4) [] (–8) – (– 4)
(b) (– 3) + 7 – (19) [] 15 – 8 + (– 9)
(c) 23 – 41 + 11 [] 23 – 41 – 11
(d) 39 + (– 24) – (15) [] 36 + (– 52) – (– 36)
(e) – 231 + 79 + 51 [] –399 + 159 + 81
Answer
(a) (-8) + (-4) [ ] (-8) – (-4)
Let us take Left Hand Side (LHS) = (-8) + (-4)
= -8 – 4
= -12
Now, Right Hand Side (RHS) = (-8) – (-4)
= -8 + 4
= -4
By comparing LHS and RHS
LHS < RHS
-12 < -4
Therefore (-8) + (-4) [<] (-8) – (-4)
(b) (-3) + 7 – (19) [ ] 15 – 8 + (-9)
Solution:-
Let us take Left Hand Side (LHS) = (-3) + 7 – 19
= -3 + 7 – 19
= -22 + 7
= -15
Now, Right Hand Side (RHS) = 15 – 8 + (-9)
= 15 – 8 – 9
= 15 – 17
= -2
By comparing LHS and RHS
LHS < RHS
-15 < -2
Therefore (-3) + 7 – (19) [<] 15 – 8 + (-9)
(c) 23 – 41 + 11 [ ] 23 – 41 – 11
Let us take Left Hand Side (LHS) = 23 – 41 + 11
= 34 – 41
= – 7
Now, Right Hand Side (RHS) = 23 – 41 – 11
= 23 – 52
= – 29
By comparing LHS and RHS
LHS > RHS
– 7 > -29
Therefore 23 – 41 + 11 [>] 23 – 41 – 11
(d) 39 + (-24) – (15) [ ] 36 + (-52) – (- 36)
Let us take Left Hand Side (LHS) = 39 + (-24) – 15
= 39 – 24 – 15
= 39 – 39
= 0
Now, Right Hand Side (RHS) = 36 + (-52) – (- 36)
= 36 – 52 + 36
= 72 – 52
= 20
By comparing LHS and RHS
LHS < RHS
0 < 20
Therefore 39 + (-24) – (15) [<] 36 + (-52) – (- 36)
(e) – 231 + 79 + 51 [ ] -399 + 159 + 81
Let us take Left Hand Side (LHS) = – 231 + 79 + 51
= – 231 + 130
= -101
Now, Right Hand Side (RHS) = – 399 + 159 + 81
= – 399 + 240
= – 159
By comparing LHS and RHS
LHS > RHS
-101 > -159
Therefore – 231 + 79 + 51 [>] -399 + 159 + 81
Ex 1.1 Class 7 Maths Question 10. A water tank has steps inside it. A monkey is sitting on the topmost step (i.e., the firststep). The water level is at the ninth step.
(i) He jumps 3 steps down and then jumps back 2 steps up.In how many jumps will he reach the water level?
(ii) After drinking water, he wants to go back. For this, hejumps 4 steps up and then jumps back 2 steps downin every move. In how many jumps will he reach backthe top step?
(iii) If the number of steps moved down is represented bynegative integers and the number of steps moved up bypositive integers, represent his moves in part (i) and (ii)by completing the following; (a) – 3 + 2 – … = – 8(b) 4 – 2 + … = 8. In (a) the sum (– 8) represents goingdown by eight steps. So, what will the sum 8 in (b)represent?
Answer
(i)
Let us consider steps moved down are represented by positive integers and then, steps moved up are represented by negative integers.
Initially monkey is sitting on the top most step i.e., first step
In 1^{st} jump monkey will be at step = 1 + 3 = 4 steps
In 2^{nd} jump monkey will be at step = 4 + (-2) = 4 – 2 = 2 steps
In 3^{rd} jump monkey will be at step = 2 + 3 = 5 steps
In 4^{th }jump monkey will be at step = 5 + (-2) = 5 – 2 = 3 steps
In 5^{th} jump monkey will be at step = 3 + 3 = 6 steps
In 6^{th} jump monkey will be at step = 6 + (-2) = 6 – 2 = 4 steps
In 7^{th} jump monkey will be at step = 4 + 3 = 7 steps
In 8^{th} jump monkey will be at step = 7 + (-2) = 7 – 2 = 5 steps
In 9^{th }jump monkey will be at step = 5 + 3 = 8 steps
In 10^{th} jump monkey will be at step = 8 + (-2) = 8 – 2 = 6 steps
In 11^{th} jump monkey will be at step = 6 + 3 = 9 steps
Therefore, monkey took 11 jumps (i.e., 9^{th} step) to reach the water level
(ii)
Let us consider steps moved down are represented by positive integers and then, steps moved up are represented by negative integers.
Initially monkey is sitting on the ninth step i.e., at the water level
In 1^{st} jump monkey will be at step = 9 + (-4) = 9 – 4 = 5 steps
In 2^{nd} jump monkey will be at step = 5 + 2 = 7 steps
In 3^{rd} jump monkey will be at step = 7 + (-4) = 7 – 4 = 3 steps
In 4^{th }jump monkey will be at step = 3 + 2 = 5 steps
In 5^{th} jump monkey will be at step = 5 + (-4) = 5 – 4 = 1 step
Therefore, monkey took 5 jumps to reach back the top step i.e., first step.
(iii)
From the question, it is given that
If the number of steps moved down is represented by negative integers and the number of steps moved up by positive integers.
Monkey moves in part (i)
= – 3 + 2 – ……….. = – 8
Then LHS = – 3 + 2 – 3 + 2 – 3 + 2 – 3 + 2 – 3 + 2 – 3
= – 18 + 10
= – 8
RHS = -8
Therefore, moves in part (i) represents monkey is going down 8 steps. Because negative integer.
Now,
Monkey moves in part (ii)
= 4 – 2 + ……….. = 8
Then LHS = 4 – 2 + 4 – 2 + 4
= 12 – 4
= 8
RHS = 8
Therefore, moves in part (ii) represents monkey is going up 8 steps. Because positive integer.
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