Question 1 State the law of conservation of mass?
Question 2 Discuss the conservation of momentum in a rocket taking off from the ground?
Question 3 A 60 g bullet fired from a 5 kg gun leaves with a speed of 500 m/s. Find the speed with which the gun recoils?
Conservation of Momentum
When two or more bodies act upon one another, their total momentum remains conserved provided no external force acts on them.
For Example : When a speeding truck hit a stationary car due to which the car also start moving.
Truck | Car | |
Velocity | Decreases | Increases |
Momentum | Decreases | Increases |
The momentum lost by truck is gained by car.
Momentum can neither be created nor destroyed .
Let us consider a truck and car are moving in same direction but with different speeds.
Truck | Car | |
Mass | m1 | m2 |
Velocity | u1 | u2 |
Initial Momentum | m1u1 | m2u2 |
Total momentum=m1u1 + m2u2
Suppose the car and truck collide for a short time t, their velocities will change.
Truck | Car | |
Mass | m1 | m2 |
Velocity | v1 | v2 |
Final Momentum | m1v1 | m2v2 |
Total Momentum = m1v1 + m2v2
Acceleration of car (a) = (v2 – u2) / t
F = m x a
F1 = Force exerted by truck on the car
F1 = m2 x (v2 – u2) / t
Acceleration of truck = (v1 – u1) / t
F2 = m1 x (v1 – u1 ) / t
F1 = – F2
m2 x (v2 – u2 )/ t = – m1 x (v1 – u1 )/ t
m2 (v2 – u2 ) = – m1 * (v1 – u1 )
m2 v2 – m2 u2 = – m1 v1 + m1 u1
m2 v2 + m1 v1 = m1 u1 + m2 u2
or
m1 u1 + m2 u2 = m2 v2 + m1 v1
Bibhudutta Behera says
Nice one useful
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