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Home » NCERT Solutions » Class 9 » Science » Chapter 13 Motion and Time

Chapter 13 Motion and Time

Last Updated on July 3, 2023 By Mrs Shilpi Nagpal

Class 7 | Science | Chapter 13 |
Motion and Time | NCERT Solutions

Question 1. Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.

Answer 1

(i) Motion of your hands while running- Oscillatory motion
(ii) Motion of a horse pulling a cart on a straight road- Straight line motion
(iii) Motion of a child in a merry-go-round-circular motion
(iv) Motion of a child on a see-saw- Oscillatory motion
(v) Motion of the hammer of an electric bell- Oscillatory motion
(vi) Motion of a train on a straight bridge-Straight line motion

Question 2. Which of the following are not correct?
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometres.
(iv) The time period of a given pendulum is constant.
(v) The speed of a train is expressed in m/h.

Answer 2 

(i) The basic unit of time is second-Correct
(ii) Every object moves with a constant speed- Not correct
(iii) Distances between two cities are measured in kilometres- Correct
(iv) The time period of a given pendulum is constant- Not correct
(v) The speed of a train is expressed in m/h- Not correct

Question 3. A simple pendulum takes 32 s to complete 20 oscillations. What is the time period of the pendulum?

Answer 3 The time period to complete one oscillation is known as time period of the pendulum.

Time period= Total time taken / Number of oscillations

Time period= 32 / 20 = 1.6 sec

Question 4. The distance between two stations is 240 km. A train takes 4 hours to cover this distance. Calculate the speed of the train.

Answer 4 Speed= Distance travelled / Time taken

Speed= 240/4 = 60 Km/hr

Question 5. The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.

Answer 5 Distance covered by car = 57336 – 57321 = 15 km

Time taken between 08:30 AM to 08:50 AM = 20 minutes= 20/60 = 1/3 hrs

Speed= Distance travelled / Time taken

Speed= 15 Km/ (1/3) hr = 45 Km/hr

Question 6. Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.

Answer 6 Speed= 2 m/s

Time taken= 15 min= 15 × 60 = 900 sec

Distance= speed × time= 2 × 900 = 1800 m = 1.8 Km

Question 7. Show the shape of the distance-time graph for the motion in the following cases:
(i) A car moving with a constant speed.
(ii) A car parked on a side road.

Answer 7  (i) A car moving with a constant speed.

Car moving with constant speed

(ii) A car parked on a side road.

Car parked on road side

 

Question 8. Which of the following relations is correct?

Chapter 13 Motion and Time Class 7

Answer 8 

speed

Question 9. The basic unit of speed is:
(i) km/min (ii) m/min
(iii) km/h   (iv) m/s

Answer 9 (iv) m/s

Question 10. A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by
the car is:
(i) 100 km (ii) 25 km
(iii) 15 km (iv) 10 km

Answer 10 (ii) 25 km

Case 1 

speed = 40 Km/h

Time= 15 min= 15/60 hr

Distance= Speed × Time = 40 × (15/60)

Distance= 10 Km

Case 2

speed = 60 Km/h

Time= 15 min= 15/60 hr

Distance= Speed × Time  = 60 × (15/60)

Distance= 15 Km

Total distance= 10 + 15 = 25 Km

Question 11. Suppose the two photographs, shown in Fig. 13.1 and Fig. 13.2, had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the fastest car.

Figure 13.1 and 13.2

Answer 11 From the figures we conclude that distance covered by blue car is 2 cm.

The distance covered = 2 × 100 =200 m

Time taken= 10 seconds

Speed = Distance/ Time

Speed= 200/ 10 = 20 m/s

Question 12. Fig. 13.15 shows the distance-time graph for the motion of two vehicles A and B. Which one of them is moving faster?
Chapter 13 Motion and Time Class 7 (1)

Fig. 13.15 Distance-time graph for the motion of two cars

Answer 12 Vehicle A is travelling longer distance in lesser time as compared to vehicle B.So, vehicle A is moving faster.

Question 13. Which of the following distance-time graphs shows a truck moving with
speed which is not constant?

Chapter 13 Motion and Time Class 7 (2)

Answer 13 (iii) Graph is not a straight line , so it shows a truck moving with speed which is not constant.

Filed Under: Science

About Mrs Shilpi Nagpal

Author of this website, Mrs. Shilpi Nagpal is MSc (Hons, Chemistry) and BSc (Hons, Chemistry) from Delhi University, B.Ed. (I. P. University) and has many years of experience in teaching. She has started this educational website with the mindset of spreading free education to everyone.

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