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Exercise 6.1 |
NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.3
Question 1 Subtract
(a) 35 – (20)
(b) 72 – (90)
(c) (–15) – (–18)
(d) (–20) – (13)
(e) 23 – (–12)
(f) (–32) – (–40)
Answer :
(a) 35 – 20 = 15
(b) 72 – 90 = –18
(c) (–15) – (–18) = –15 + 18 = 3
(d) –20 – (13) = –20 – 13 = –33
(e) 23 – (–12) = 23 + 12 = 35
(f) (–32) – (–40) = –32 + 40 = 8
Question 2 Fill in the blanks with >, < or = sign:
(a) (–3) + (–6) _______________ (–3) – (–6)
(b)(–21) – (–10) _______________ (–31) + (–11)
(c) 45 – (–11) _______________ 57 + (–4)
(d)(–25) – (–42) _______________ (–42) – (–25)
Answer :
(a) (–3) + (–6) < (–3) – (–6)
(b) (–21) – (–10) > (–31) + (–11)
(c) 45 – (–11) > 57 + (–4)
(d) (–25) – (–42) > (–42) – (–25)
Question 3 Fill in the blanks:
(a) (–8) + __________ = 0
(b) 13 + __________ = 0
(c) 12 + (–12) = __________
(d)(–4) + __________ = –12
(e) __________ – 15 = –10
Answer :
(a) (–8) + 8 = 0
(b) 13 + (–13) = 0
(c) 12 + (–12) = 0
(d) (–4) + (–8) = –12
(e) 5 – 15 = –10
Question 4 Find: (a) (–7) – 8 – (–25)
(b)(–13) + 32 – 8 – 1
(c) (–7) + (–8) + (–90)
(d) 50 – (–40) – (–2)
Answer :
(a) (–7) – 8 – (–25)
= –7 – 8 + 25
=–15 + 25
=10
(b) (–13) + 32 – 8 – 1
= –13 + 32 – 8 – 1
= 32 – 22
= 10
(c) (–7) + (–8) + (–90)
= –7 – 8 – 90
= –105
(d) 50 – (–40) – (–2) = 50 + 40 + 2
= 92