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Home » NCERT Solutions » Class 11 » Maths » NCERT Solutions for Exercise 4.1, Class 11, Maths

NCERT Solutions for Exercise 4.1, Class 11, Maths

Exercise 4.1
Complex Numbers and Quadratic Equations
Question and Answers
Class 11 – Maths

Class Class 11
Subject Mathematics
Chapter Name Complex Numbers and Quadratic Equations
Chapter No. Chapter 4
Exercise Exercise 4.1
Category Class 11 Maths NCERT Solutions

Question 1 Express each of the complex number in the form a + ib.

(5i) (-3/5i)

Answer

(5i) (-3/5i)
= 5 x (-3/5) x i2
= -3 x -1       [i2 = -1] = 3
(5i) (-3/5i) = 3 + i0

Question 2 Express the given complex number in the form a + ib

i9 + i19

Answer

i9 + i19 = (i2)4. i + (i2)9. i
= (-1)4 . i + (-1)9 .i
= 1 x i + -1 x i
= i – i
= 0
Hence,
i9 + i19 = 0 + i0

Question 3 Express the given complex number in the form a + ib

i-39

Answer

i−39 = i −4×9−3
=(i 4)−9 . i−3
=(1)−9 . i−3         [i4=1]

Exercise 4.1 , Answer 3

Question 4 Express the given complex number in the form a + ib

3 ( 7 + i 7) + i ( 7 + i 7 )

Answer

3(7 + i 7) + i (7 + i 7) =  21 +21 i + 7 i+ 7 i2
=21+28 i+7×(−1)       [ i2=−1] = 14 + 28 i

Question 5 Express the given complex number in the form a + ib

Answer

(1 – i ) – (–1 + i 6)
= (1−i)−(−1+ i 6)
= 1- i + 1 -6 i
2 – 7 i

Question 6 Express the given complex number in the form a + ib

Exercise 4.1 , Question 6

Answer

Exercise 4

Question 7 Express the given complex number in the form a + ib

Exercise 4.1 , Question 7

Answer

Exercise 4.1 , Answer 7

Question 8 Express the given complex number in the form a + ib

(1 – i )4

Answer

(1 – i) 4 = [(1 – i)2]2
= [1 + i2 – 2i]2
= [1 – 1 – 2i]2 [i2 = -1] = (-2i)2
= 4(-1)
= -4
Hence, (1 – i)4 = -4 + 0i

Question 9 Express the given complex number in the form a + ib

Exercise 4.1 , Question 9

Answer

Exercise 4.1 , Answer 9

Question 10 Express the given complex number in the form a + ib

Exercise 4.2 , Question 10

Answer

Exercise 4.2 , Answer 10

Question 11 Find the multiplicative inverse of given complex numbers  4 – 3i

Answer

Let z =4- 3i
z̄= 4 + 3i and | z | 2 = 42+(−3)2 = 16+9 = 25
Thus, the multiplicative inverse of 4 – 3i is given by z-1
Z -1 = z̄ / | z | 2
Z -1 = (4 + 3i) / 25
Z -1 = 4/25 + 3i /25

Question 12 Find the multiplicative inverse of the complex number √5 + 3i

Answer

z = √5 + 3i
z̄ = √5 – 3i
| z |2 = ( √5 )2 + 32
| z |2 = 14

Exercise 4.1 , Answer 12

Question 13 Find the multiplicative inverse of the complex number −i.

Answer

Let z=−i
Then, z̄ =  i
| z |2 = 1
The multiplicative inverse of the complex number −i
Z -1 = z̄ / | z | 2
Z-1 = i / 1
Z-1 = 1

Question 14  Express the following expression in the form of a + ib :

Question 14, Exercise 4.1

Answer

Answer 14 , Exercise 4.1

Filed Under: Class 11, Maths, NCERT Solutions

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