• Skip to main content
  • Skip to secondary menu
  • Skip to primary sidebar

Class Notes

Free Class Notes & Study Material

  • Class 1-5
  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • NCERT SOL
  • Ref Books
Home » NCERT Solutions » Class 11 » Maths » NCERT Solutions for Exercise 1.5, Class 11, Maths

NCERT Solutions for Exercise 1.5, Class 11, Maths

Last Updated on July 11, 2023 By Mrs Shilpi Nagpal

Exercise 1.5 Sets
Question and Answers
Class 11 – Maths

Class Class 11
Subject Mathematics
Chapter Name Sets
Chapter No. Chapter 1
Exercise Exercise 1.5
Category Class 11 Maths NCERT Solutions

Question 1) Let U = { 1, 2, 3, 4, 5, 6, 7, 8, 9 } A = { 1, 2, 3, 4}, B = { 2, 4, 6, 8 } and

C = { 3, 4, 5, 6 }.Find

(i) A′

(i) A′= U−A

 A’ = {1,2,3,4,5,6,7,8,9} − {1,2,3,4}

A’ ={5,6,7,8,9}

(ii) B′

(ii) B′= U−B 

B’ = {1,2,3,4,5,6,7,8,9} − {2,4,6,8}

B’ = {1, 3, 5, 7, 9}

(iii) (A ∪ C)′

(iii) A U C = {1, 2, 3, 4, 5, 6}

(A ∪ C)′ = U− (A u C)

(A ∪ C)′   = {1,2,3,4,5,6,7,8,9} − {1,2,3,4,5,6}

(A ∪ C)’ = {7, 8, 9}

(iv) (A ∪ B)′

(iv) A U B = {1, 2, 3, 4, 6, 8}

(A ∪ B)′ = U− (A ∪ B)

(A ∪ B)′  ={1,2,3,4,5,6,7,8,9} − {1,2,3,4,5,6,8}

(A ∪ B)’ = {5, 7, 9}

(v) (A′)′

(v) (A’)’ = A = {1, 2, 3, 4}

(vi)  (B – C)′

(vi) B – C = {2, 8}

(B−C)′ = U− (B−C)

(B−C)′ = {1,2,3,4,5,6,7,8,9} − {2,8}

(B – C)’ = {1, 3, 4, 5, 6, 7, 9}

Question 2 If U = { a, b, c, d, e, f, g, h}, find the complements of the following sets :

(i) A = {a, b, c}

(i) A = {a, b, c}

The complement of set A is the set of all elements of U which are not the elements of A.

A′=U−A

A’ = {a,b,c,d,e,f,g,h} − {a,b,c}

So we get

A’= {d, e, f, g, h}

(ii) B = {d, e, f, g}

(ii)  B = {d, e, f, g}

The complement of set B is the set of all elements of U which are not the elements of B.

B′=U−B

B’ = {a,b,c,d,e,f,g,h} − {d,e,f,g}

So we get

B’ = {a, b, c, h}

(iii) C = {a, c, e, g}

(iii) C = {a, c, e, g}

The complement of set c is the set of all elements of U which are not the elements of C.

C′=U−C

C’ = {a,b,c,d,e,f,g,h} − {a,c,e,g}

So we get

C’ = {b, d, f, h}

(iv) D = { f, g, h, a}

(iv) D = {f, g, h, a}

The complement of set D is the set of all elements of U which are not the elements of D.

D′=U−D

D’ = {a,b,c,d,e,f,g,h} − {f,g,h,a}

So we get

D’ = {b, c, d, e}

Question 3 Taking the set of natural numbers as the universal set, write down the complements of the following sets:

(i) {x : x is an even natural number}

(i) The set of natural number is the universal set.

∴ {x:x is an even natural number}′ = {x:x is an odd natural number}

(ii) { x : x is an odd natural number }

(ii) The set of natural number is the universal set.

 {x: x is an odd natural number}´ =  {x: x is an even natural number}

(iii) {x : x is a positive multiple of 3}

(iii) The set of natural number is the universal set.

{x: x is a positive multiple of 3}´ = {x: x ∈ N and x is not a multiple of 3}

(iv) { x : x is a prime number }

(iv) The set of natural number is the universal set.

{x: x is a prime number}´ ={x: x is a positive composite number and x = 1}

(v) {x : x is a natural number divisible by 3 and 5}

(v) The set of natural number is the universal set.

{x: x is a natural number divisible by 3 and 5}´ = {x: x is a natural number that is not divisible by 3 or 5}

(vi) { x : x is a perfect square }

(vi) The set of natural number is the universal set.

{x: x is a perfect square}´ = {x: x ∈ N and x is not a perfect square}

(vii) { x : x is a perfect cube}

(vii) The set of natural number is the universal set.

{x: x is a perfect cube}´ = {x: x ∈ N and x is not a perfect cube}

(viii) { x : x + 5 = 8 }

(viii) The set of natural number is the universal set.

{x: x + 5 = 8}´ = {x: x ∈ N and x ≠ 3}

(ix) { x : 2x + 5 = 9}

(ix) The set of natural number is the universal set.

{x: 2x + 5 = 9}´ = {x: x ∈ N and x ≠ 2}

(x) { x : x ≥ 7 }

(x) The set of natural number is the universal set.

{x: x ≥ 7}´ = {x: x ∈ N and x < 7}

(xi) { x : x ∈ N and 2x + 1 > 10 }

(xii) The set of natural number is the universal set.

{x: x ∈ N and 2x + 1 > 10}´ = {x: x ∈ N and x ≤ 9/2}

Question 4 If U = {1, 2, 3, 4, 5, 6, 7, 8, 9 }, A = {2, 4, 6, 8} and B = { 2, 3, 5, 7}. Verify that

(i) (A ∪ B)′ = A′ ∩ B′

(i) A∪B = {2,4,6,8} ∪ {2,3,5,7}

A∪B = {2,3,4,5,6,7,8}

(A∪B)′ = U = A∪B  =  {1, 9}

A′= U−A =  {1,3,5,7,9}

B′= U − B  = {1,4,6,8,9}

A’ ∩ B’ = {1, 3, 5, 7, 9} ∩ {1, 4, 6, 8, 9} = {1, 9}

Therefore, (A U B)’ = A’ ∩ B’.

(ii) (A ∩ B)′ = A′ ∪ B′

(ii) A ∩ B = {2,4,6,8} ∩ {2,3,5,7} = {2}

(A ∩ B)′ = U− A ∩ B = {1,3,4,5,6,7,8,9}

A′= U− A  = {1,3,5,7,9}

B′= U−B  = {1,4,6,8,9}

A′∪ B′ = {1,3,5,7,9} ∪ {1,4,6,8,9} = {1,3,4,5,6,7,8,9}

Therefore, (A ∩ B)’ = A’ U B’.

Question 5 Draw appropriate Venn diagram for each of the following :

(i) (A ∪ B)′,

(i) (A U B)’

NCERT Solutions Class 11 Chapter 1 Ex 1.5 Image 1

(ii) A′ ∩ B′,

(ii) A’ ∩ B’

NCERT Solutions Class 11 Chapter 1 Ex 1.5 Image 2

(iii) (A ∩ B)′,

(iii) (A ∩ B)’

NCERT Solutions Class 11 Chapter 1 Ex 1.5 Image 3

(iv) A′ ∪ B′

(iv) A’ U B’

NCERT Solutions Class 11 Chapter 1 Ex 1.5 Image 4

Question 6 Let U be the set of all triangles in a plane. If A is the set of all triangles with at least one angle different from 60°, what is A′?

Answer U is the set of all triangles in the plane

A = Set of triangles different form 60°

A′=U−A = Set of all equilateral triangles

∴ A′ is the set of all equilateral triangles

Question 7 Fill in the blanks to make each of the following a true statement :

(i) A ∪ A′ = . . .

(i) The union of the set and its complement is the universal set

∴ A ∪ A′=U

(ii) φ′ ∩ A = . . .

(ii) ∅′∩ A = U ∩ A = A

∴ ∅′ ∩ A = A

(iii) A ∩ A′ = . . .

(iii) The intersection of the set and its complement is an empty set.

A ∩ A’ = Φ

(iv) U′ ∩ A = . . .

∅ ∩ A = U′ ∩ A = ∅

∴ U’ ∩ A = Φ

Filed Under: Class 11, Maths, NCERT Solutions

About Mrs Shilpi Nagpal

Author of this website, Mrs. Shilpi Nagpal is MSc (Hons, Chemistry) and BSc (Hons, Chemistry) from Delhi University, B.Ed. (I. P. University) and has many years of experience in teaching. She has started this educational website with the mindset of spreading free education to everyone.

Reader Interactions

Leave a Reply

Your email address will not be published. Required fields are marked *

Primary Sidebar

  • Facebook
  • Pinterest
  • Twitter
  • YouTube

CATEGORIES

  • —— Class 6 Notes ——
  • —— Class 7 Notes ——
  • —— Class 8 Notes ——
  • —— Class 9 Notes ——
  • —— Class 10 Notes ——
  • —— NCERT Solutions ——

© 2016 - 2025 · Disclaimer · Privacy Policy · About Us · Contact Us