• Skip to main content
  • Skip to secondary menu
  • Skip to primary sidebar

Class Notes

Free Education for All

  • Class 1-5
  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • NCERT Solutions
    • NCERT Books

Chapter 1 Real Numbers

Exercise 1.4

Last Updated on April 1, 2021 By Mrs Shilpi Nagpal Leave a Comment

NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Exercise 1.4 Page 17 1. Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion: (i) 13/3125 (ii) 17/8 (iii) 64/455 (iv) 15/1600 (v) 29/343 (vi) 23/(2352) (vii) 129/(225775) (viii) 6/15 … [Read more...] about Exercise 1.4

Exercise 1.3

Last Updated on April 1, 2021 By Mrs Shilpi Nagpal Leave a Comment

NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Ex 1.3 Page 14   1. Prove that √5 is irrational. Answer : Let's assume, that √5 is rational number. i.e. √5 = x/y (where, x and y are co-primes) y√5= x Squaring both the sides, we get, (y√5)2 = x2 ⇒ 5y2 = x2……………………………….. (1) Thus, x2 is divisible by 5, so x is also divisible by … [Read more...] about Exercise 1.3

Exercise 1.2

Last Updated on April 1, 2021 By Mrs Shilpi Nagpal Leave a Comment

NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Ex 1.2 Page 11   1. Express each number as a product of its prime factors: (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429 Answer : (i) 140 By Taking the LCM of 140, we will get the product of its prime factor. Therefore, 140 = 2 × 2 × 5 × 7 × 1 = 22×5×7 (ii) 156 By Taking the LCM of 156, we … [Read more...] about Exercise 1.2

Exercise 1.1

Last Updated on April 1, 2021 By Mrs Shilpi Nagpal Leave a Comment

NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers Ex 1.1 Page 7 1. Use Euclid’s division algorithm to find the HCF of : (i) 135 and 225 (ii) 196 and 38220 (iii) 867 and 255 Answer : (i) 135 and 225 In this given question, 225 is greater than 135. Therefore, by Euclid’s division algorithm, we have, 225 = 135 × 1 + 90 Now, remainder 90 ≠ 0, thus again … [Read more...] about Exercise 1.1

Primary Sidebar

Recent Posts

  • Chapter 7 The Last Leaf
  • Chapter 6 Weathering the Storm in Ersama
  • Chapter 5 The Happy Prince
  • Chapter 4 In the Kingdom of Fools
  • Chapter 3 Iswaran the Storyteller
  • Chapter 2 The Adventures of Toto
  • Chapter 1 The Lost Child
  • Chapter 11 If I were You
  • Chapter 10 Kathmandu
  • Email
  • Facebook
  • Pinterest
  • RSS
  • Twitter

Copyright © 2022 · About Us · Contact Us · Privacy Policy